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g^2-20g-21=0
a = 1; b = -20; c = -21;
Δ = b2-4ac
Δ = -202-4·1·(-21)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-22}{2*1}=\frac{-2}{2} =-1 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+22}{2*1}=\frac{42}{2} =21 $
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